4HCl(aq) + MnO2(s) →2H2O(l) + MnCl2(aq) + Cl2(g) How many grams of HCl react with 5.00 g of manganese dioxide, according to this equation?

8.39 grams ##HCl## will react with 5.00 grams of ##MnO_2##

##4HCl + MnO_2 -> 2H_2O + MnCl_2 + Cl_2##

For this reaction determine the mass of HCl that will react with 5.00 grams of manganese dioxide.

This is a basic problem of mass to mass conversions.

## "grams" -> "moles" -> "moles" -> "grams"##

Mass of ##MnO_2 = 54.94 + 2(15.99) = "86.92 g MnO"_2## Mass of ##HCl = 1.01 + 35.45 = "36.46 g HCl"##

##5.00 cancel("g MnO"_2) xx (1 cancel("mol MnO"_2))/(86.92 cancel("g MnO"_2)) xx (4 cancel("mol HCl"))/(1cancel("mol MnO"_2)) xx "36.46 g HCl"/(1 cancel("mol HCl"))##

The middle conversion factor is to mole ratio from the balance chemical equation of ##"4 mol HCl"## for ##"1 mol MnO"_2##

##((5.00) (4) (36.46))/(86.92)##

##"8.39 grams HCl"##

Here is a gram to gram video explanation.

http://bit.ly/1kljEVR