Waiting for answer This question has not been answered yet. You can hire a professional tutor to get the answer.

QUESTION

# 5 grams of Methane (CH3OH) react with 10 grams of oxygen (O2), how many grams of carbon dioxide (CO2)will be formed?

NOTE: CH_3OH is methanol and CH_4 is methane.

I will solve for both since both undergo combustion reaction.

So, 1) 5 g of CH_3OH. The molecular mass of CH_3OH is 12+3+16+1=32 g mol^-1 So, the moles of CH_3OH are 5/32=0.15625  mol 10 g of O_2 has 10/32=0.3125 mol

The combustion of methanol produces CO_2 and H_2O

So, 2CH_3OH+3O_2->2CO_2+4H_2O

Hence, 2 mol of methanol requires 3 mol oxygen to undergo complete reaction. So, 0.15625 mol of methanol will require 0.234375 mol oxygen to undergo complete reaction.

Since, amount of oxygen supplied is in excess of what is required entire amt. of methanol will be exhausted.

From the equation, 2 mol of methanol produces 2 mol carbon dioxide 0.15625 mol of methanol will produce 0.15625 mol of carbon dioxide.

The mass of carbon dioxide=44xx0.15625=6.875 g

2) 5 g of CH_4. The molecular mass of CH_3OH is 12+4=16 g mol^-1 So, the moles of CH_4 are 5/16=0.3125  mol 10 g of O_2 has 10/32=0.3125 mol

The combustion of methane produces CO_2 and H_2O

So, CH_4+2O_2->CO_2+2H_2O

Hence, 1 mol of methane requires 2 mol oxygen to undergo complete reaction. So, 0.3125 mol of methanol will require 0.625 mol oxygen to undergo complete reaction.

Since, amount of oxygen supplied is less than what is required entire amt. of methanol will not be used up. So, here oxygen is the limiting reactant. The amt. of oxygen available will dictate the amt. of carbon dioxide produced.

From the equation, 2 mol of oxygen produces 1 mol carbon dioxide 0.3125 mol of oxygen will produce 0.15625 mol of carbon dioxide.

The mass of carbon dioxide=44xx0.15625=6.875 g

I hope that was helpful. Please take care while naming chemical .