A physical ( compound ) pendulum of a hollow-disk of radius R = 1 40 + 2 x da) cm consists of two symmetric holes of radius 13.

Please answer this question for me, and d6 is 4. Thanks!!

A physical ( compound ) pendulum of a hollow-disk of radius R = 1 40 + 2 x da) cm consists of twosymmetric holes of radius 13. cm each , plus one solid disk of radius 15 em attached on the front size .The solid disk attachment has the same material and thickness of the hollow - disk pendulum ."35 CM30 cm30 cmSuppose the mass-density factor " for the pendulum and solid disk is & KE /'m _ and the pivot O is at 30cIn from the center of the full disk , calculate the followings : -(a ) The rotational inertia loverall of the hollow - disk pendulum at an axis passing through the plane ofpaper and the pivot O.19 marks )16 ) The distance hem of the center of mass of the hollow - disk pendulum from the pivot 0 . 19 marks !(C ) The angular frequency W .15 marks )(d) Period T .12 marks )