A puck of mass 0.60 kg approaches a second, identical puck that is stationary on frictionless ice. The initial speed of the moving puck is 4.0 m/s.

0.604.0v1v2v1v2.

understand I need to use formulas: V=V1cos(30) +V2cos(60) and 0=V1sin(30)-V2sin(60) but I do not at all understand how to combine them to solve for both variables. I have tried using substitution but my answers were vastly different than the actual answers. Please describe algebraic steps as though I have never seen math before.