A sample of argon gas has a volume of 6 liters at a temperature of 7 °C. What volume does the gas occupy at 147 °C?

##if p_1 = p_2 -> V_2 = 9 ## ##l##

If this process is isobaric (meaning that pressure stays the same [iso ##->## same, bar ##->## pressure]) then it is true (for ideal gases, like argon) that volume is directly proportional with temperature.

formula-wise:

##V_1/T_1 = V_2/T_2##

Caution: Always give tempreature in K (Kelvin) when doing anything with gases, as these formulas only work with absolute temperature!

In this case:

##T_1 = 7 + 273 = 280 K## ##T_2 = 147 + 273 = 420 K## ##V_1 = 6## ##l## ##V_2 = ?##

generally:

##V_1/T_1 = V_2/T_2 -> V_2 = T_2 * V_1/T_1##

so

##(6 l)/(280 K) = V_2 / (420 K) -> V_2 = 420 K * (6l)/(280K) = 9 l##