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QUESTION

A solid sample of Fe(OH)2 is added to 450.0 mL of 0.550 M aqueous HCl. The resulting solution is acidic. It takes 95.0 mL of 0.500 M NaOH solution to neutralize the solution. Answer the following qu

A solid sample of Fe(OH)2 is added to 450.0 mL of 0.550 M aqueous HCl. The resulting solution is acidic.  It takes 95.0 mL of 0.500 M NaOH solution to neutralize the solution.  Answer the following questions:

  1. How would you prepare 1.50 L of the 0.550 M HCl solution from a 12 M concentrated HCl Solution?
  1. How many moles of HCl are in the initial solution? 
  1. What was the mass of Fe(OH)2 (89.86 g/mol) added to the HCl solution?
  1. What is the final concentration (Molarity) of the Cl- ion and OH- in the final solution?
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*** ***** you ******* *** * ** the **** * *** solution **** * 12 * ************ *** ****************** the ****** ** *** M *** ****** ** make 15L of **** * HClM1V1 = M2V2V2 * *** ** ***** **** = 01875L ****** into * ******** * ********* **** **** * 500ml ********** ******** **** ********* *** ***** of 12M *** ** * ****** ********** flask *** ***** to the ***** ***** *** ***** ****** ******* *** ****** mark on *** flaskThe ******** ********* *** *** 0550M ****** many ***** ** *** *** ** *** ******* ************** * molarity ** volume = ***** × **** = **************** was *** mass ** Fe(OH)2(8986 ****** ***** ** *** *** solution?Mass = ***** ** ************ **** ***** **** (aq) * *** **** *** ******** * H2O(l)Moles ** NaOH * **** ** ** ********** Moles ** ****** *** = ********** ***** mole ratio)Moles ** *** that reacted with ******** ****** - 00475] * 02molesReaction Fe **** * + **** *** ***** * ********* ** ** ***** **** reacted( *** added) * (02÷ 2) = 01 **** **** ********* of ** ******* ***** = ** ** ***** 8986g What is *** ***** concentration ********** ** *** ****** *** ***** the final ************** ** ********* *** * ********** ** 450ml   Cl- * ****** ** ******* *** * 010556MOH- * ***

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