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QUESTION

# A solution contains 3.95g of CS2 and 2.43g CH3COCH3.vapor pressures at 35°C of pure CS2 and pure CH3COCH3 are 616 torr and 332 torr respectively.Assume ideal ,calculate vapor pressure of each component n the total vapor pressure?

The total vapor pressure is "489 torr".

This problem requires you to have some idea about Raoult's Law, which allows you to calculate the partial vapor pressure of a liquid that's part of a mixture by using the vapor pressure of the pure substance and its mole fraction in the mixture.

color(blue)(P_"A" = chi_"A" * P_"A"^@)" ", where

P_"A" - the partial vapor pressure of the component; chi_"A" - fraction of the component; P_"A"^@ - the vapor pressure of the pure component.

You need to use the molar masses of the two substances to find how many moles of each you have. For carbon disulfide you have

3.95color(red)(cancel(color(black)("g"))) * "1 mole"/(76.13color(red)(cancel(color(black)("g")))) = "0.0519 moles CS"""_2

For acetone, you have

2.43color(red)(cancel(color(black)("g"))) * "1 mole"/(58.08color(red)(cancel(color(black)("g")))) = "0.0418 moles" ("CH"""_3)_2"CO"

The total number of moles in the mixture is

n_"total" = n_(CS_2) + n_((CH_3)_2CO)

n_"total" = 0.0519 + 0.0418 = "0.0937 moles"

The mole fraction of carbon sulfide is

chi_(CS_2) = n_(CS_2)/n_"total"

chi_(CS_2) = (0.0519color(red)(cancel(color(black)("moles"))))/(0.0937color(red)(cancel(color(black)("moles")))) = "0.554"

The mole fraction of acetone is

chi_"acetone" = n_"acetone"/n_"total"

chi_"acetone" = (0.0418color(red)(cancel(color(black)("moles"))))/(0.0937color(red)(cancel(color(black)("moles")))) = "0.446"

This means that the partial vapor pressure of carbon disulfide is

P_(CS_2) = chi_(CS_2) * P_(CS_2)^@

P_(CS_2) = 0.554 * "616 torr" = color(green)("341 torr")

The partial vapor pressure of acetone will be

P_"acetone" = 0.446 * "332 torr" = color(green)("148 torr")

The total vapor pressure will be

P_"total" = P_(CS_2) + P_"acetone"

P_"total" = "341 torr" + "148 torr" = color(green)("489 torr")

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