Answered You can hire a professional tutor to get the answer.
A solution of perchloric acid was prepared and standardized using the primary standard Na2CO3. If 0.2068 g Na2CO3 required 36.31 mL HClO4 calculated...
A solution of perchloric acid was prepared and standardized using the primary standard Na2CO3. If 0.2068 g Na2CO3 required 36.31 mL HClO4 calculated the concentration of HClO4 in M.
Na2CO3 + 2 HClO4 = CO2 + H2O + 2 NaClO4Molwt of Na2CO3 = 106g0.2068 g Na2CO3 contains 0.2068/106 = 2 mmolSo, 4 mmol of HClO4 are required.4mmol in 36.31ml = 4/36.31 = 0.11M