A student determines the value of the equilibrium constant to be 2.0010 7 for the following reaction. Fe(s) + 2HCl(aq)FeCl 2 (s) + H 2 (g) Based on...

A student determines the value of the equilibrium constant to be 2.00×107 for the following reaction.

Fe(s) + 2HCl(aq)FeCl2(s) + H2(g)

Based on this value of Keq:

G° for this reaction is expected to be (greater, less)  than zero. 

Calculate the free energy change for the reaction of 1.80 moles of Fe(s)at standard conditions at 298K.

    G°rxn =   kJ