Answered You can hire a professional tutor to get the answer.
A student has a solution containing a mixture of metal cations: Cu +2 , Cr +2 , and Fe +3 , each a solution with NO 3 - anion.
A student has a solution containing a mixture of metal cations: Cu+2, Cr+2, and Fe+3, each a solution with NO3- anion. Adding a concentrated solution of NH4OH(aq) caused the precipitation of Cr+2 and Fe+3 as insoluble hydroxides. The Cu+2 remained in solution and forms the complex ion Cu(NH3)4+2. Which balanced complete ionic equations represent each of these reactions? Check all that apply.
Cu+2(aq) + 4NH4+(aq) +4OH-(aq) → Cu(NH3)4+2(aq) + 4H2O(l)
Cu+2(aq) + 4NH4+(aq) +4OH-(aq) → Cu(NH3)4+2(s) + 4H2O(l)
Cu+2(aq) +2NO3-(aq) + 4NH4+(aq) + 4OH-(aq) → Cu(NH3)4+2(aq) + 2NO3-(aq) + 4H2O(l)
Cu+2(aq) +2NO3-(aq) + 4NH4+(aq) + 4OH-(aq) → Cu(NH3)4+2(s) + 2NO3-(aq) + 4H2O(l)
Cu(NO3)2(aq) + 4NH4OH(aq) → Cu(NH3)4+2(aq) + 2NO3-(aq) + 4H2O(l)
Cu(NO3)2(aq) + 4NH4OH(aq) → Cu(NH3)4+2(s) + 2NO3-(aq) + 4H2O(l)
Cr+2(aq) + 2OH-(aq) → Cr(OH)2(s)
Cr+2(aq) + 2OH-(aq) → Cr(OH)2(aq)
Cr+2(aq) +2NO3-(aq) + 2NH4+(aq) + 2OH-(aq) → Cr(OH)2(s) + 2NO3-(aq) + 2NH4+(aq)
Cr+2(aq) +2NO3-(aq) + 2NH4+(aq) + 2OH-(aq) → Cr(OH)2(aq) + 2NO3-(aq) + 2NH4+(aq)
Cr(NO3)2(aq) + 2NH4OH(aq) → 2NH4NO3(aq) + Cr(OH)2(s)
Cr(NO3)2(aq) + 2NH4OH(aq) → 2NH4NO3(aq) + Cr(OH)2(aq)
Fe+3(aq) + 3OH-(aq) → Fe(OH)3(s)
Fe+3(aq) + 3OH-(aq) → Fe(OH)3(aq)
Fe+3(aq) +3NO3-(aq) + 3NH4+(aq) + 3OH-(aq) → Fe(OH)3(s) + 3NO3-(aq) + 3NH4+(aq)
Fe+3(aq) +3NO3-(aq) + 3NH4+(aq) + 3OH-(aq) → Fe(OH)3(aq) + 3NO3-(aq) + 3NH4+(aq)
Fe(NO3)2(aq) + 3NH4OH(aq) → 3NH4NO3(aq) + Fe(OH)3(s)
Fe(NO3)2(aq) + 3NH4OH(aq) → 3NH4NO3(aq) + Fe(OH)3(aq)