According to the following reaction, how many grams of hydrogen iodide will be formed upon the complete reaction of 33.0 grams of iodine with excess hydrogen gas? hydrogen (g) + iodine (s) hydrogen iodide (g)

33.26 g of ##HI## will be formed.

33.26 g of HI will be formed.

##H_(2(g))+I_(2(g))rarr2HI_((g))##

1mol + 1mol ##rarr## 2mol

Using approximate ##A_r## values:

##(2xx127)gI_2rarr2(1+127)gHI##

So:

##254grarr256g##

So:

##1grarr256/254g##

So:

##33.0grarr(256)/(254)xx33.0= 33.26g##