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According to the following reaction, how many moles of Fe(OH)2 can form from 175.0 mL of 0.227 M LiOH solution? I have tried this a few times and not getting the correct answer of 1.99x10(-2) moles. I started with 0.277 M LiOH/0.175L.

First of all, you should not try to get the answer by randomly multiplying/dividing numbers. This is guessing, not solving.

According to reaction, 1 mole ##Fe(OH)_2## forms from 2 moles of LiOH.

So if we know how many moles of LiOH is used we can find how many moles of Fe(OH)2 will be formed.

is moles per volume. And we know that 0.227M means that 1 L of LiOH solution contains 0.227 moles of LiOH.

Then, if we multiply the volume to moles per volume, we will get the number of moles in that given volume. Such as:

0.175 L of LiOH ##* (0.227 mol of LiOH)/(1L of LiOH)## = 0.0397 mol of LiOH is used.

Note that 175mL equals to 0.175L.

Now that we know how many moles of LiOH is consumed we can find the number of moles of Fe(OH)2 formed:

0.0397 mol of LiOH##*(1 molof Fe(OH)_2)/(2 mol of LiOH)## = ##1.99*10^-2## moles of ##Fe(OH)_2##.

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