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QUESTION

# Convert 255 mmHg into atm. And convert 620 torr into psi

THE CONVERSION RATIOS

There is a conversion factor for going from "mm Hg" (or "torr") to "atm":

\mathbf("1 atm" = "760 mm Hg" = "760 torr")

There also exists a conversion factor for "PSI". I actually don't know it, so I looked it up: https://www.google.com/?gws_rd=sslq=psi+to+torr

Turns out it's \mathbf("51.7149 torr = 1 PSI").

(Google is a great resource. You should practice with it!)

PERFORMING THE CONVERSIONS

(1)

Let's start from the equality we just wrote out.

"1 atm" = "760 mm Hg"

What happens if we divide by "1 atm"? We get the actual ratio for the conversion.

(1 cancel"atm")/(1 cancel"atm") = 1 = "760 mm Hg"/"1 atm" = "1 atm"/"760 mm Hg"

This implies that multiplying by this ratio does NOT change the validity of your answer... only the units. (It preserves your numerical information.)

Thus, we get:

color(blue)(P_"atm") = 255 cancel"mm Hg" xx "1 atm"/(760 cancel"mm Hg")

= color(blue)("0.336 atm")

So now you have the same pressure in different units.

(2)

Like before, we have a ratio that is equal to 1:

1 = "51.7149 torr"/"1 PSI" = "1 PSI"/"51.7149 torr"

This ratio is used as follows:

color(blue)(P_"torr") = 620 cancel"torr" xx "1 PSI"/(51.7149 cancel"torr")

= color(blue)("12.0 torr")

Again, the same pressure as "620 torr", but in different units.