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# Convert 255 mmHg into atm. And convert 620 torr into psi

**THE CONVERSION RATIOS**

There is a **conversion factor** for going from ##"mm Hg"## (or ##"torr"##) to ##"atm"##:

##\mathbf("1 atm" = "760 mm Hg" = "760 torr")##

There also exists a conversion factor for ##"PSI"##. I actually don't know it, so I looked it up: https://www.google.com/?gws_rd=sslq=psi+to+torr

Turns out it's ##\mathbf("51.7149 torr = 1 PSI")##.

(Google is a great resource. You should practice with it!)

**PERFORMING THE CONVERSIONS**

**(1)**

Let's start from the equality we just wrote out.

##"1 atm"## ##=## ##"760 mm Hg"##

What happens if we divide by ##"1 atm"##? We get the actual ratio for the conversion.

##(1 cancel"atm")/(1 cancel"atm")## ##= 1## ##= "760 mm Hg"/"1 atm" = "1 atm"/"760 mm Hg"##

This implies that multiplying by this ratio does NOT change the validity of your answer... only the units. (It preserves your numerical information.)

Thus, we get:

##color(blue)(P_"atm") = 255 cancel"mm Hg" xx "1 atm"/(760 cancel"mm Hg")##

##=## ##color(blue)("0.336 atm")##

So now you have the **same** pressure in **different** units.

**(2)**

Like before, we have a ratio that is equal to ##1##:

##1 = "51.7149 torr"/"1 PSI" = "1 PSI"/"51.7149 torr"##

This ratio is used as follows:

##color(blue)(P_"torr") = 620 cancel"torr" xx "1 PSI"/(51.7149 cancel"torr")##

##=## ##color(blue)("12.0 torr")##

Again, the **same** pressure as ##"620 torr"##, but in **different** units.