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* ******** of the **** *** ******************************************* adjacent ******** ** a **** is: ******************************************** ***** ******* *** ******* is ***** *** ****************************************************** **************** ********* ** have: ****************** ********************************************** rangle}{\sqrt{1^2+1^2+1^2}\cdot{\sqrt{1^2+1^2+0^2} }} \:=\:\frac{1\+\1\+\0}{\sqrt{3}\cdot\sqrt{2}}[/tex]Therefore: ******************************************************* \;\;\theta ***********************