# How do you solve #4(y-2/4)=9(y+1/3) #?

##### 1 Answer

Dec 20, 2015

#### Explanation:

According to BEDMAS, work on the brackets first. Reduce

#4(y-1/2)=9(y+1/3)#

Make the bracketed terms have the same denominator.

#4((2y)/2-1/2)=9((3y)/3+1/3)#

Subtract the bracketed terms.

#4((2y-1)/2)=9((3y+1)/3)#

Reduce the fractions by cancelling.

#color(red)cancelcolor(black)4^2((2y-1)/color(red)cancelcolor(black)2)=color(blue)cancelcolor(black)9^3((3y+1)/color(blue)cancelcolor(black)3)#

Rewrite the equation.

#2(2y-1)=3(3y+1)#

Multiply.

#4y-2=9y+3#

Isolate for

#4y-9y=3+2#

Solve.

#-5y=5#

#y=-1#