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# Find the amount in Grams of Fe2O3 required to make 1000 Kilograms of Fe. 2Fe2O3 + 3C ------> 4Fe + 3Co2?

##1.430 × 10^6color(white)(l) "g Fe"_2"O"_3##

**1.** Find the number of moles of Fe you need to make by dividing mass by .

Since you need grams at the end, convert kilograms to grams first.

1000 kg = 1 000 000 g.

Divide by 55.85 g/mol Fe.

1 000 000 g ÷ 55.85 g/mol Fe = 17 905 mol Fe.

**2.** The ratio of ##Fe_2O_3## to ##Fe## is 2:4, so you'll need half as much ##Fe_2O_3## as ##Fe##.

So, divide your answer by 2.

##"17 905 mol Fe" ÷ "2 mol Fe/mol Fe"_2"O"_3 = "8952.6 mol Fe"_2"O"_3##

**3.** Multiply this number by the formula mass of ##Fe_2O_3##:

##"8952.6 mol Fe"_2"O"_3 × "((55.85×2)+(16.00×3)) g/mol Fe"_2"O"_3 = 1.430 × 10^6 "g Fe"_2"O"_3##.