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Find the equation of the line tangent to the curve of f(x) = 4x 3 at x = -2. Hint: An equation of a line has two components: a slope and a...
Find the equation of the line tangent to the curve of f(x) = 4x3 at x = -2.
Hint: An equation of a line has two components: a slope and a y-intercept. First find the slope (recall the definition of a derivative) and then use the slope and the point (-2, f(-2)) to find the y-intercept.
I got half way through the problem and found the solution 48 for the first part and -32 for the value of x
Please show how you would work the problem and I can figure out how to incorporate y= mx+c into the numbers I got. I am stuck between the first and fourth choice.
The choices for this homework problem are
y= 48x+32
y= 48
y= 12x2 -2
y= 48x +64
y= 12x2
Business Analysis 2372 thanks for help