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QUESTION
Given the following balanced reaction, if a mixture of 1.50 mol of Al and 3.00 mol of Cl2 are allowed to react, how many moles of AlCl3 are formed,
Given the following balanced reaction, if a mixture of 1.50 mol of Al and 3.00 mol of Cl2 are allowed to react, how many moles of AlCl3 are formed, assuming a 75% yield?2 Al (s) + 3 Cl2 (g) → 2 AlCl3 (s)
