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QUESTION
He general form of the equation of a circle is 7x2 + 7y2 − 28x + 42y − 35 = 0.The equation of this circle in standard form is (x - 2)^2 + (y + 3)^2 = 5 (x - 2)^2 + (y + 3)^2 = 18 (x - 4)^2 + (y +
He general form of the equation of a circle is 7x2 + 7y2 − 28x + 42y − 35 = 0.
The equation of this circle in standard form is (x - 2)^2 + (y + 3)^2 = 5 (x - 2)^2 + (y + 3)^2 = 18 (x - 4)^2 + (y + 6)^2 = 24 (x + 4)^2 + (y - 6)^2 = 24 (x + 2)^2 + (y - 3)^2 = 35 . The center of the circle is at the point (-14, 21) (-2, 3) (2, -3) (-4, 6) (4, -6) , and its radius is 5^(1/2) 3(2^(1/2)) 2(6^(1/2)) 35^(1/2) units.
