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QUESTION

# How can I calculate the partial pressure of a dry gas?

We must use the following equation:

P_"dry gas" = P_"total" - P_"water vapor"

Suppose that a sample of hydrogen gas is collected over water at 14.0 °C. The pressure of the resultant mixture is 113.0 kPa. What is the pressure that is exerted by the dry hydrogen alone?

DATA:

P_"total" = "113.0 kPa" × "760 mmHg"/"101.3 kPa" = 847.8 mmHg

From Table,

P_"water vapor"= 11.99 mmHg

P_"total" = ?

SOLUTION:

Now, by inserting the values, we get

P_"dry gas" = P_"total" - P_"water vapor"

P_"dry gas" = 847.8 mmHg - 11.99 mmHg

P_"dry gas" = 835.8 mmHg