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How can I calculate the partial pressure of a dry gas?
Please read Dalton's law of .
We must use the following equation:
##P_"dry gas" = P_"total" - P_"water vapor"##
Suppose that a sample of hydrogen gas is collected over water at 14.0 °C. The pressure of the resultant mixture is 113.0 kPa. What is the pressure that is exerted by the dry hydrogen alone?
DATA:
##P_"total" = "113.0 kPa" × "760 mmHg"/"101.3 kPa"## = 847.8 mmHg
From Table,
##P_"water vapor"##= 11.99 mmHg
##P_"total"## = ?
SOLUTION:
Now, by inserting the values, we get
##P_"dry gas" = P_"total" - P_"water vapor"##
##P_"dry gas"## = 847.8 mmHg - 11.99 mmHg
##P_"dry gas"## = 835.8 mmHg