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QUESTION

# How can I write the Lewis dot structure for C2H6?

The first step in drawing the for ethane (C_2H_6) is to determine how many are available for the molecule.

Since C has 4 , and each H atoms contributes 1 valence electron, the total number of electrons will be

2*4 + 6*1 = 14 "e"^(-)

This means that the Lewis dot structure for C_2H_6 must account for 14 , either through between atoms, or through lone pairs.

So, the two C atoms are placed in the center of the molecule. Each C atom forms three with three H atoms, with one aditional covalent bond being formed between the two C atoms.

Each of these seven single bonds contains 2 electrons, which means that a total of

7 * 2 = 14 "e"^(-) were used for the C_2H_6 molecule.