How do you find the exact value of ##sin60°cos30° + sin30°cos60°##?

##30^o " and " 60^o "are angles of one of the standard triangles"##

##sin(30^o) = 1/2##

##cos(30^o) = sqrt(3)/2##

##sin(60^o) = sqrt(3)/2##

##cos(60^o) = 1/2##

So ##sin(60^o)*cos(30^o) + sin(30^o)*cos(60^o)##

##=(sqrt3/2)(sqrt3/2) +(1/2)(1/2) = 3/4 +1/4##

##=1##