Waiting for answer This question has not been answered yet. You can hire a professional tutor to get the answer.
How do you find the integral of ##x^3 * sin( x^2 ) dx##?
##I=1/2(-x^2cosx^2+sinx^2)+C##
##x^2=t => 2xdx=dt, x^3dx=1/2x^2 2xdx = 1/2tdt##
##int x^3 sinx^2 dx = 1/2 int tsintdt = I##
##u=t => du=dt##
##dv=sintdt => v=int sintdt= -cost##
##I=1/2[-tcost + int costdt] = 1/2(-tcost+sint)+C##
##I=1/2(-x^2cosx^2+sinx^2)+C##