# How do you find the vertical asymptotes of the function y= (x^2+1)/(3x-2x^2) ?

The vertical asymptotes of y=(x^2+1)/(3x-2x^2) are x=0 and x=3/2.

To find the vertical asymptotes we set the denominator equal to zero.

3x-2x^2=x(3-2x)=0rArrx=0 or x=3/2

Look at the graph below.

Sometimes, the denominator is equal to zero at the same x-value that makes the numerator zero. This will produce a instead of a vertical asymptote.