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QUESTION

# How do you find the zeros of the function f(x)= x^2-2x-4?

The zeros of this function are x_1=1-sqrt(5) and x_2=1+sqrt(5)

To find the zeros of a quadratic function you first have to calculate Delta. In this case it is Delta = (-2)^2-4*1*(-4) = 20 Delta > 0  so function has 2 real zeros which can be calculated using:

x_1=(-b-sqrt(Delta))/(2a) and x_2 = (-b+sqrt(Delta))/(2a)