How do you solve 32 to the power of 2/5?

Your final answer is 4.

##x = (32)^(2/5)## can be solved by using the exponent rule for : ##x^(m/n) = root(n)(x^m)##. So, we can rewrite ##(32)^(2/5)## as ##root(5)(32^2)##

##32^2## evaluates to 1024, and ##root(5)(1024)##, or the 5th root of 1024 (what times itself 5 times equals 1024) equals 4.