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How do you write ##sqrt(160)## in simplified radical form?
##4sqrt10##
##sqrt160##
= ##sqrt((16)(10)##
= ##4sqrt10##
Waiting for answer This question has not been answered yet. You can hire a professional tutor to get the answer.
##4sqrt10##
##sqrt160##
= ##sqrt((16)(10)##
= ##4sqrt10##
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