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QUESTION
How doyou find the derivative of ##2sinxcosx##?
##2sinxcosx=sin2x##
using the , the derivative is ##2cos2x##
Here is how, ##d/dx(sinx)=cosx## The chain rule for this case is ##d/dx(sinf(x))=f'(x)*cosf(x)##
Thus ##d/dx(sin2x)=2cos2x##
