How many grams of lithium nitrate will be needed to make 250 grams of lithium sulfate, assuming that you have an adequate amount of lead (IV) sulfate to do the reaction? Pb(SO4)2 + 4 LiNO3  Pb(NO3)4 + 2 Li2SO4

313 g of ##LiNO3## is needed.

Step 1: Calculate the number of mol of ##Li2SO4## ##(n(Li2SO4))## ##n(Li2SO4)## = mass/molar mass = 250/109.9 = 2.27 mol (3sf)

Step 2: Use the ratio from equation to find ##n(LiNO3)## 'What you want over what you got' ##n(LiNO3) = 4/2 X n(Li2SO4)## = 2 X 2.27 = 4.55 mol

Step 3: Calculate the mass of LiNO3 using the molar mass ##mass(LiNO3) = n X mm## = 4.55 X 68.9 = 313 g (3sf)

Keep the values in your calculator to avoid truncation and round at the final answer.