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QUESTION

# How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---&gt; 2 NaCl + 3 O2

How many grams of NaCl are produced if 80.0 grams of O_2 are produced?

We begin with a balanced chemical equation that is provided in the question.

2NaClO_3 -> 2NaCl + 3O_2

Next we determine what we have and what we want. We have 80.0 grams of Oxygen and we want grams of Sodium Chloride.

We set up a roadmap to solve the problem

grams O_2 -> mol O_2 -> mol NaCl -> grams NaCl

We need the molar mass (gfm) of O_2 and NaCl. O_2 = 31.98 g/mol and NaCl = 58.44 g/mol.

We need ratio between O_2:NaCl 3:2. This comes from the coefficients of the balanced chemical equation.

Now we set up conversion factors following the roadmap from above. Unit we want in the numerator, unit to cancel in the denominator.

80.0 g O_2 x (1 mol O_2)/(31.98 g O_2) x (2mol NaCl)/(3 mol O_2) x(58.44 g NaCl)/(1 mol NaCl) =

Multiply the numerators, and divide the denominators.

The outcome is 97.5 g NaCl will be produced with 80.0 grams O_2

I hope this was helpful. SMARTERTEACHER

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