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QUESTION

How many moles of atoms are in 3.00 g of ""^13C?

There are 3/13xxN_A" carbon atoms", where N_A="Avogadro's Number, "6.022xx10^23*mol^-1

In 13*g of ""^(13)C there are precisely "Avogadro's number of atoms".You have specified 3.00*g, thus there are (3.00*g)/(13.00*g*mol)xx6.022xx10^23*mol^-1 = ??""^13C " atoms"