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How much energy is required to melt a 20.0 lb bag of ice ar 0 C? a pond of ice is equivalent to 0.4536 kg. The delta Hfusion of ice is + 6.009 KJ/mol.
##3030kJ##
Your method is 100% correct, but you made a small calculation error in converting the lb to g, by a factor of 10, resulting in you final answer being out by a factor of 10.
The amount of energy required to melt ##1kg## of ice at ##0^@C## is equal to the specific latent heat of fusion for ice and has value ##L_f=334kJ//kg##.
So for ##20xx0.4536=9.072kg##, we get that energy required to melt it is ##W=mL_f=9.072kgxx334000J//kg##
##=3.03MJ##
##=3030kJ##