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# How will you prepare a 1:80 dilution?

The answer Rogan wrote is correct, but his example is a little off.

Adding **80 mL** of water to **1 mL** of stock solution will produce a **1:81** , not a **1:80** one.

The ratio between the final volume of the solution, the one you get after diluting the initial sample, and the initial volume of the sample will give you the dilution factor So,

##"DF" = V_"final"/V_"initial"##

If you've got a **1-mL** sample, and the dilution factor is **1:80**, you'd get

##V_"final" = "DF" * V_"aliquot" = 80 * 1 = "80 mL"##

However, this volume **includes** the volume of the aliquot, the original sample you wanted to dilute, which means that the **80-mL** final volume will include **1 mL** of sample, the rest being the volume of the diluent

##V_"diluent" = V_"final" - V_"aliquot" = 80 - 1 = "79 mL"##

So, to make a **1:80** dilution for a **1-mL** sample, you add enough water to get the final volume to **80 mL** ##->## in this example, you would add **79 mL** of water to the **1-mL** sample.

If you add **80 mL** of water, you'll get a dilution of **1:81**

##"DF" = (80 + 1)/1 = 81##