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QUESTION

# How would you balance Na2CO3(s) + HCl(aq) = NaCl(aq) + H2O(l) + CO2(g)?

Na_2CO_3(s) + color(red)(2)HCl(aq) -> color(red)(2)NaCl(aq) + H_2O(l) + CO_2(g)

Na_2CO_3(s) + color(red)(2)HCl(aq) -> color(red)(2)NaCl(aq) + H_2O(l) + CO_2(g)

The reasoning that you should follow in order to balance this reaction easily is:

1- Look at the Na. You have 2 in Na_2CO_3 and 1 in NaCl then you should multiply NaCl by color(red)(2).

2- When multiplying NaCl by 2, we will have to Cl in the products side, therefore, we should multiply HCl by color(red)(2).

3- Look at the carbon atom C there is one atom at each side. No need for any action.

4- Look at the hydrogen atom H there is 2 atoms at each side. No need for any action.

5- Look at the oxygen atom O there is 3 atoms in Na_2CO_3 and there is 1 atom in H_2O and 2 atoms in CO_2 which makes it a total of 3 atoms. No need for any action.

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