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How would you balance Na2CO3(s) + HCl(aq) = NaCl(aq) + H2O(l) + CO2(g)?
##Na_2CO_3(s) + color(red)(2)HCl(aq) -> color(red)(2)NaCl(aq) + H_2O(l) + CO_2(g)##
##Na_2CO_3(s) + color(red)(2)HCl(aq) -> color(red)(2)NaCl(aq) + H_2O(l) + CO_2(g)##
The reasoning that you should follow in order to balance this reaction easily is:
1- Look at the ##Na##. You have ##2## in ##Na_2CO_3## and ##1## in ##NaCl## then you should multiply ##NaCl## by ##color(red)(2)##.
2- When multiplying ##NaCl## by 2, we will have to ##Cl## in the products side, therefore, we should multiply ##HCl## by ##color(red)(2)##.
3- Look at the carbon atom ##C## there is one atom at each side. No need for any action.
4- Look at the hydrogen atom ##H## there is 2 atoms at each side. No need for any action.
5- Look at the oxygen atom ##O## there is 3 atoms in ##Na_2CO_3## and there is 1 atom in ##H_2O## and 2 atoms in ##CO_2## which makes it a total of 3 atoms. No need for any action.
