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QUESTION

# How would you calculate the number of grams of sodium oxide, Na2O, that will be produced when 5.00 moles react with oxygen given the reaction: 4Na + O2--&gt; 2 Na2O?

4Na + O_2 rarr 2Na_2O.

By the of this reaction if 5 mol natrium react, then 2.5 mol Na_2O should result.

The molecular mass of natrium oxide is 61.98 g*mol^(-1). If 5 mol natrium react, then 5/2 molxx61.98 g*mol^(-1) = 154.95 g natrium oxide should result.

So what have I done here? First, I had a balanced chemical equation (this is the important step; is it balanced?). Then I used the stoichiometry to get the molar quantity of product, and converted this molar quantity to mass. If this is not clear, I am willing to have another go.

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