I'm very confused. A sample of 1.00 L of gas at NTP conditions contains 20% oxygen and 80% nitrogen. Calculate the number of moles of each gas.

Could anyone help me with this. I'm very confused.

4. A sample of 1.00 L of gas at NTP conditions contains 20% oxygen and 80% nitrogen. Calculate the number of moles of each gas. Below are my calculations, but they don't match other answers. I don't know what I did wrong.

1.00 L / 22.4 L/mol = 0.04464 moles

  .04464 /5 = .008928 per 20%

  20% = .008928 mole

  80% = .008928 x 4 = .03571 mole