I need help understanding the following questions: i. If you conducted this coupling step under acidic conditions, how would you expect the reaction rate to be affected? ii. Would you expect

I need help understanding the following questions:

   i.     If you conducted this coupling step under acidic conditions, how would you expect the reaction rate to be affected?

   ii. Would you expect to obtain the same product under acidic conditions? If not, what would the major product be?

I understand the NaOH was deprotonating to allow for more resonance. Thus, I believe the acidic conditions should slow the rate.