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If 79.2 grams of magnesium nitride are mixed with excess water, then how many moles of NH3 are produced?
If 79.2 grams of magnesium nitride are mixed with excess water, then how many moles of NH3 are produced?Mg3N2 + 6H2O => 2NH3 + 3Mg(OH)2 a1.57 b12.9 c2.89 d3.33 e6.66 f1.23
