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QUESTION
If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation hequalsminus16t squaredplusvtplus
If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation hequalsminus16t squaredplusvtpluss, where h is in feet. If the object is propelled from a height of 12 feet with an initial velocity of 64 feet per second, its height h is given by the equation hequalsminus16t squaredplus64tplus12. After how many seconds is the height 40 feet?
