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If f ( x ) = 4 x 2 − 2 x + 3 f ( x ) = 4 x 2 - 2 x + 3 , find f ' ( − 5 ) f ′ ( - 5 ) . Use this to find the equation of the tangent line to the parabola y = 4 x 2 − 2 x + 3 y = 4 x 2 - 2
If
f
(
x
)
=
4
x
2
−
2
x
+
3
f
(
x
)
=
4
x
2
-
2
x
+
3
, find
f
'
(
−
5
)
f
′
(
-
5
)
.
Use this to find the equation of the tangent line to the parabola
y
=
4
x
2
−
2
x
+
3
y
=
4
x
2
-
2
x
+
3
at the point
(
−
5
,
113
)
(
-
5
,
113
)
. The equation of this tangent line can be written in the form
y
=
m
x
+
b
y
=
m
x
+
b
where
m
m
is:
and where
b
b
is: