In a survey of 2795 adults, 1428 say they have started paying bills on line in the past year. Construct a 99% confidence interval for the population...

In a survey of 2795 adults, 1428 say they have started paying bills on line in the past year.

Construct a 99% confidence interval for the population proportion. Interpret the results

n = 2795 and α = 0.01 →r pˆx ± zα/2 pˆx = 1428= 0.51092795 zα/2 = z0.005 = 2.5758 rpˆx (1 − pˆx )0.5109(0.4891)= 0.5109 ± 2.5758= 0.5109 ± 0.0244 = (0.4865, 0.5353)n2795 1