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QUESTION
let a1 = 1, a(n+1) = 3*a(n) + 2 for n=1.
let a1 = 1, a(n+1) = 3*a(n) + 2 for n>=1. show that a(n) = 2*3^(n-1) - 1 for n>=1
Given A(1) =1A(N+1) = 3*A(N)+2 A(N+1) – A(N) = 2 A(N) +2 [A(N+1)+1] – [A(N)+1] = 2 *(A(N) +1)Defining new series B(N) = A(N) +1 B(N+1)- B(N) = 2*B(N) B(N+1) = 3B(N) [B(N+1)/B(N)] = 3So B(N)...