Let f(x)=(-4e^(x+1))+(e^6).

Let f(x)=(-4e^(x+1))+(e^6).f'(0)=

Let f(x) = -4e(x+1) + e6. Find f’(0)Solution: The differentiation of f(x) is:⇒ −4e ( x +1) So f’(0) = -4e(0 + 1) = -4e [Differentiation of e6 would be zero as it is a constant]