Maximize 2 = 32 + 6 + 20 Subject to : 1 . a + 6 + 30 lt; 30 2 . 2 2 + 26 + 50 lt; 24 3 . 42 + 6 + 20 lt; 36 4 . 2 , 6 , ( 2 0 NB : a =...

Maximize z = 3a + b + 2c and the rest is on the picture

Maximize 2 = 32 + 6 + 20Subject to :"1 .a + 6 + 30 < 302 .2 2 + 26 + 50 < 243 .42 + 6 + 20 < 364 .2 , 6 , ( 2 0NB : a = Computers 6 = Network devices c = IP camerasZ = Performance- Numbers are costs .The problem above consist of maximizing the performance of our computer network by reducing*the total cost .