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Na-DDTC is a metal chelating agent often used to preconcentrate heavy metals in preperation for quantitative analysis.

Na-DDTC is a metal chelating agent often used to preconcentrate heavy metals in preperation for quantitative analysis. For this question, Pb2+ will be complexed with Na-DDTC then partitioned into chloroform. The relevant parameters are pKa=3.95, KL=2.3*10^3, logB=10.3, log KM=6.8. If 100mL of a 20 ppm aqueous Pb2+ solution is treated with 25 mg of Na-DDTC then extracted with 25 mL of chloroform, calculate the percent lead extracted as a function of pH (0-14).Formulas to be used:KL= [HL]organic/[HL]aqueousD= [KM][B][Ka][HL]org/([KL][H+]aq)My Work:1.5*10^-4 mol Na-DDTC / 0.1 L = 1.5*10^-5 M of NaDDTC9.7*10^-6 M of Pb2+ (Is this even relevant information?)[HL]org = KL*[HL]aq = 2.3*10^3 * 1.5*10^-5 = 3.5*10^-2[KM][B][Ka][HL]org/([KL][H+]aq) = ([10^6.8][10^10.3][10^-3.95][3.5^-2])/([2.3*10^3][H+]aq) ?I just need to find D and I can calculate q from there. I am just not sure how to calculate D as it seems the numbers are not working out. What is [H+]aq ? It is negative inverse log of pH? Or do I use the lead info?Please just quickly show me how to solve for D at one pH.

Na-DDTC is a metal chelating agent often used to preconcentrate heavy metals in preperationfor quantitative analysis. For this question, Pb2+ will be complexed with Na-DDTC thenpartitioned into...
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