Need an argumentative essay on Statistical Methods Assignment. Needs to be 4 pages. Please no plagiarism.Download file to see previous pages... Since this is a weight reduction study, we did a one-dir

Need an argumentative essay on Statistical Methods Assignment. Needs to be 4 pages. Please no plagiarism.

Since this is a weight reduction study, we did a one-directional t test. Results showed that the diet resulted in a significant decrease in weight, both for a 90% and 95% confidence level.

In both cases, it is reasonable to say that two-thirds of the general population agrees with the principle of University top-up fees. The hypothesized p is included in both intervals. We, therefore, do not reject the null hypothesis.

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: 0.05p = 2*0.0096 = 1 - 0.9808 = 0.0192

The test shows that there is a significant statistical difference between the sample mean and the hypothesized mean, on a 95% confidence level. We, therefore, reject the null hypothesis.

Question 6

sample size121degree of freedom120

sample mean47.50critical t1.658

sample standard deviation7.50

90% confidence interval(46.37, 48.63)

Assuming that the population standard deviation is equal to the sample standard deviation, the confidence interval becomes:

(46.38, 48.62)

The two intervals do not seem to have a significant difference between them. This is a result of having a large sample size. As the sample size increases, the difference between the two intervals is also expected to significantly increase, resulting to large errors.

Question 7

t ratio

3.364

alpha ()

critical t

0.05

2.306

reject H0

0.10

1.860

reject H0

In this test, we assume that the sample standard deviation approximates that of the population without any significant statistical difference. Since this is a weight reduction study, we did a one-directional t test. Results showed that the diet resulted in a significant decrease in weight, both for a 90% and 95% confidence level.

Question 8

T

680

N

1050

T/n

0.648

p

0.667

standard deviation

0.228

Test Statistic1.29

(1.29)0.9015

p value0.1970

95% confidence interval(0.619, 0.677)

90% confidence interval(0.623, 0.672)

In both cases, it is reasonable to say that two-thirds of the general population agrees with the principle of University top-up fees. The hypothesized p is included in both intervals. We, therefore, do not reject the null hypothesis.