Please note I have attached the table with the values I have completed

Table 1: Copper Gluconate Formula DataMass(g) ofMass (g) ofcopper Gluconate wrapper Mass (g) ofwrapper + Cu Mass (g) ofCu Mass (g) ofgluconate 1g 2.6g 0.1g 0.9g 2.5g (show all work to receive credit)Moles of Cu recovered 0.1gCu=63.546 g/mol0.1g/63.546 g/mol = 1.5x10-3 mol Moles of Gluconate0.9 g Gluconate (C12H22O14)C=12.0107 g/mol X 12= 144.1284 g/molH= 1.008 g/mol X 22= 22.176 g/molO= 15.999X14=223.986 g/mol144.1284+22.1760+223.986= 390.29 g/mol0.9g X 1mol /390.29 g/mol = 2.3x10-3 mol Experimental Chemical Formula Cu(copper) mol Gluconate molCu(0.00113/0.00113) Gluconate 0.00220/0.00133= Cu1 Gluconate2Formula Cu(c6H11O7)2 Post-lab Questions1. List two sources of error in the experiment and explain the impact they had on theresults. I feel two sources of error in this experiment are if you are poor at math(whichI am and have spent several hours on this lab). You could also misuse the scsale andnot zero it and thus skew your weights and get poor results. The copper wasextremely hard to handle and I and if you used anything besides the provided stir rodyou can take copper from your solution by it getting on gloves and other things. 2. Using your own lab results, calculate the percent composition for each element in thecompound copper gluconate. Clearly label each element and the percentage. You mustshow all work (not just the formula) to receive credit.Cu 13.9% H 4.9% C 31.8% O 49.4%