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Problem 1. (a) State the inverse function theorem for functions of a single variable. (You don't need to prove it.) (b) Let I R be an open interval, and let g : I ! R be a smooth function. Let J be th
Problem 1. (a) State the inverse function theorem for functions of a single variable.
(You don't need to prove it.)
(b) Let I R be an open interval, and let g : I ! R be a smooth function. Let J
be the range of g, i.e. J = g(I). Prove that if g0(t) 6= 0 for all t 2 I, then there
exists a smooth function f : J ! I which is the inverse to g, i.e. g f = 1J , and
f g = 1I . Hint: Use part (a).
(c) Prove that the function f has the property that, for all t 2 J, we have
f0(t) =
1
g0(f(t))
: (1)
Problem 2. Let : I ! R3 be a regular smooth curve, (not necessarily parametrized
by arc length). Let g : I ! R be the arc length of . Set J = g(I), and let f
be the inverse of g. For the existence of g, we refer to Problem 1. Recall that the
curve = f : J ! R3 is parametrized by arc length, (you don't need to prove
this). By de nition, the curvature of at s 2 I, is the curvature of at f 1, i.e.
k (s) = k (f 1(s)). In this problem, we're going to nd a formula for the curvature of
.
(a) Prove that, for all s 2 I we have
00(f 1(s)) = 00(s) (f0(f 1(s)))2 + 0(s) f00(f 1(s)):
1
(b) Use Eq. 1 to express f0(g(s)) in terms of k 0(s)k, and then use the result to prove
that, for all s 2 I
f00(g(s)) =
00(s) 0(s)
k 0(s)k4 :
HINT: First prove that
d
ds
k 0(s)k =
00(s) 0(s)
k 0(s)k
:
(c) Use parts (a) and (b) to show that
k 00(f 1(s))k2 =
1
k 0(s)k6
k 00(s)k2k 0(s)k2 ( 00(s) 0(s))2
;
and, then take the square root of both sides of this equation, and use an appropriate
formula for the cross product, to prove
k (s) =
k 00(s) 0(s)k
k 0(s)k3 : (2)
Problem 3. Consider the smooth curve : R ! R2, de ned as
(t) =
e t
p
2 + 1
(cos(t); sin(t)):
(a) Determine its velocity 0(t), and show that is not parametrized by arc length.
(b) Determine the curvature k (t) of . HINT: use Equation 2.
(c) Find a reparametrization of so that it is parametrized by arc length. That is, nd
a smooth bijective function f : I ! R with smooth inverse f 1 : R ! I, such that
the smooth curve = f : I ! R2 is parametrized by arc length. (HINT: Start
by determining the arc length of .)
(d) Determine the curvature of , and compare with part (b).
Problem 4. Consider the smooth curve : (0;1) ! R3, de ned as
(t) = (e t
8 cos(t); e t
8 sin(t); t):
(a) Sketch the trace of , and in the same gure, draw the tangent line of at t = =2.
(b) Compute the curvature k and the torsion of .
(c) Set a(t) = 00(t), and de ne
a?(t) = a(t)
a(t) 0(t)
k 0(t)k
:
2
Recall that the unit normal is then de ned by
n (t) =
a?(t)
ka?(t)k
:
Calculate n (t).
(d) The osculating circle of at t0 2 (0;1) is the trace of the curve
(s) =
1
k (t0)
cos(s)
0(t0)
k 0(t0)k
+ sin(s)n (t0)
+ (t0) +
1
k (t0)
n (t0):
Set t0 = and draw the corresponding osculating circle Draw the trace of in the
same picture.