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QUESTION
Show that the function f(x) = x^(1/3) is continuous at x = 1. Here we define for x positive x^(1/3) = l. {y gt; 0 : y^3 lt; x}.
Show that the function f(x) = x^(1/3) is continuous at x = 1. Here we define for x positive x^(1/3) = l.u.b. {y > 0 : y^3 < x}.
Show that the sequence {an} given by an = (1 + 1/n^2) is a Cauchy sequence
