Silver chloride, often used in silver plating, contains 75.27% Ag. What is the mass of silver chloride required to plate 245 mg of pure silver?

The answer is 0.326 g, or 326 mg.

The answer is ##"0.326 g"##, or ##"326 mg"##.

SInce silver chloride, or ##"AgCl"##, contains ##"75.27%"## silver, you know for a fact that you will need more than 245 mg of silver chloride in order to have 245 mg of pure silver. Every 100 g of silver chloride will contain 75.27 g of pure silver.

The amount of pure silver you need represents 75.27% of the amount of silver chloride you must use, which means that

##"245 mg Ag" * ("100 g AgCl")/("75.27 g Ag") = "326 mg AgCl"##

That is how much silver chloride you need in order to plate 245 mg of pure silver.