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QUESTION

# Silver chloride, often used in silver plating, contains 75.27% Ag. What is the mass of silver chloride required to plate 245 mg of pure silver?

The answer is 0.326 g, or 326 mg.

The answer is "0.326 g", or "326 mg".

SInce silver chloride, or "AgCl", contains "75.27%" silver, you know for a fact that you will need more than 245 mg of silver chloride in order to have 245 mg of pure silver. Every 100 g of silver chloride will contain 75.27 g of pure silver.

The amount of pure silver you need represents 75.27% of the amount of silver chloride you must use, which means that

"245 mg Ag" * ("100 g AgCl")/("75.27 g Ag") = "326 mg AgCl"

That is how much silver chloride you need in order to plate 245 mg of pure silver.